PinguZard Posted March 1, 2015 Share Posted March 1, 2015 i know very less about the breeding system. we make use of those items given in island 4 in kanto to bring out the dominating iv stat. what I intend to ask is how should one plan for 3x31 iv . for e.g. my dragonite has 2x31 n my sceptile 1x31 how should i make the child have 3x31? Link to comment
Munya Posted March 1, 2015 Share Posted March 1, 2015 (edited) i know very less about the breeding system. we make use of those items given in island 4 in kanto to bring out the dominating iv stat. what I intend to ask is how should one plan for 3x31 iv . for e.g. my dragonite has 2x31 n my sceptile 1x31 how should i make the child have 3x31? If you want to guarantee a 3x31 what you need to do is, have 2 2x31's with 1 of the 31's being in the same stat, such as. Attack Defense Mother Defense Speed Father Then you brace the attack on the mother, and the speed on the father, the defense will average out regardless of if it passes or not and you will result in a 31 no matter what. So you would end up with a 31 attack, defense, and speed child. Edited March 1, 2015 by Munya PinguZard 1 Link to comment
PinguZard Posted March 1, 2015 Author Share Posted March 1, 2015 If you want to guarantee a 3x31 what you need to do is, have 2 2x31's with 1 of the 31's being in the same stat, such as. Attack Defense Mother Defense Speed Father Then you brace the attack on the mother, and the speed on the father, the defense will average out regardless of if it passes or not and you will result in a 31 no matter what. So you would end up with a 31 attack, defense, and speed child. Thanks a lot. Link to comment
Qaztin Posted March 3, 2015 Share Posted March 3, 2015 U can also gamble iv :D U can pass maximum 2 iv by braces and 1 random iv without brace, and the other ev is average of mothers and father. 31 x ->passed via brace y 31->passed via brace 31 x ->gambled 31 31->average = 31 y x ->average =(x+y)/2 y x ->average =(x+y)/2 as u see best result can be 31/31/31/31/Z/Z, but u got like 12,5% chance for that result in that kind of sytuation :) Link to comment
PinguZard Posted March 11, 2015 Author Share Posted March 11, 2015 U can also gamble iv :D U can pass maximum 2 iv by braces and 1 random iv without brace, and the other ev is average of mothers and father. 31 x ->passed via brace y 31->passed via brace 31 x ->gambled 31 31->average = 31 y x ->average =(x+y)/2 y x ->average =(x+y)/2 as u see best result can be 31/31/31/31/Z/Z, but u got like 12,5% chance for that result in that kind of sytuation :) u mean to say that after bracing the 2 respective ivs one can be gambled and the remaining others will be the average O_o woahhh! i was unaware of the gambling part. 12.5% becomes rare them. will try it. thanls a lot :) Link to comment
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