RenDude Posted April 28, 2022 Share Posted April 28, 2022 (edited) From what I understand: During shiny breeding, 4 IVs will be picked at random (provided there's no braces involved) and of these 4, 2 will be the highest possible while 2 will be averaged. If that's the case, would that mean that to breed a 5*31 natured shiny comp, I can go with a female 4*31 (without nature) and a 5*31 male with nature, since there are only 2 IVs left that aren't the same/31s? So I could just give the 5*31 natured mon an everstone and get the last needed 31 AND nature. Edited April 28, 2022 by RenDude ZoroarkH 1 Link to comment
hannahtaylor Posted April 28, 2022 Share Posted April 28, 2022 Unfortunately, 31s count as one of the rolls even though they're both 31. If it's not braced, it's a roll. RenDude and Quinn010 2 Link to comment
RenDude Posted April 28, 2022 Author Share Posted April 28, 2022 3 minutes ago, hannahtaylor said: Unfortunately, 31s count as one of the rolls even though they're both 31. If it's not braced, it's a roll. Good thing I asked before I wasted money, thanks for the info! Link to comment
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